Tuesday, May 12, 2015

NATE Do the correct day! I'm no longer here to tell you the day, figure it out!

WORDS!!!!!!!!!!!!!!!!!!!!!!!!!!!

Thursday, May 7, 2015

Due Friday, May 15
direct and inverse variation problems 1-5, and 9-13
Due Thursday, May 14
section 2.5 (again) problems
  • 3rd day, no hints this time
  • 11
  • 12
section 2.5 additional problems problems
  • 1 
  • 2
  • 5
Due Wednesday, May 13
section 2.5 problems

  • 6 
    • Is the table direct, inverse or neither?
    • If it is direct or inverse, what is the equation?
  • 7 - the "constant of variation" is k
  • 8 - the distance from the fulcrum is inversely proportional to the weight of the person, therefore distance and weight are x and y. If a seesaw is balanced, k on one side must equal the k on the other side.
  • 9b - same as problem 8
  • 10 
    • the number of students raising money is inversely proportional to how much money each student needs to raise. 
    • $10,000 is k
    • 10b, graph using calculator, important! Set window so your points fill the screen, make xmin=0 and ymin=0. What should xmax and ymax be? xscl and yscl can be anything.


Due Tuesday, May 12

section 2.5 problems

  • 1 just rewrite into y=k/x form
  • 2 solve for k to make the equation, then use the equation 
  • 3 use the equation 
  • 4 
    • define x and y
    • solve for k
    • if k is the same for each of the three situations then it is inverse. If k is different it is not inverse variation
  • 5 "time it takes to travel a given distance is inversely proportional to how fast you travel". The distance you travel is constant so it is k. The "time" and the "how fast you travel" (speed) are y and x.


In class Monday, May 11

  • Read introduction
  • Skip investigation
  • Read Example A
  • Read definition of Inverse Variation 
  • Read Example B
  • Conduct the "ruler-balance" investigation (Example B)
Due Monday, May 11
section 2.4 additional problems problems 2, 3, 4, 5
section 2.4 problem 10, 11